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Grade 12th passIntegral Calculus

integration root cos2A/sinA=

udaybhansingh

11 Years agoGrade 12th pass

1 Answer

Jitender Singh

11 Years ago

Ans:
Hello student,
Please find the answer to your question below

$I = \int \frac{cos2A}{sinA}dA$
$I = \int \frac{1-2sin^{2}A}{sinA}dA$
$I = \int cosecAdA - 2\int sinAdA$
$I = \int cosecAdA - 2(-cosA)$
$I = \int \frac{1+tan^{2}\frac{A}{2}}{2tan\frac{A}{2}}dA + 2cosA$
$I = \int \frac{sec^{2}\frac{A}{2}}{2tan\frac{A}{2}}dA + 2cosA$
$I = log(tan\frac{A}{2})+ 2cosA+c$

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