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integrate [x^2]dx , limit of integration= 0 to 1.5
Between0and1the function is0, integral0. Between1and2v, the function is1, integral(1)(2v-1). Between2vand1.5, the function is2, integral(2)(1.5-2v). Add up and simplify. I think you will get2-2vthanks and regardssunil kraskIItian faculty
integration 0 to 1.5 (x^2)=[x^3/3]limits 0 to 1.5 =(1.5^3/3)-(0^3/3) =(3.375/3)-(0) =1.125
integration 0 to 1.5 (x^2)dx=[x^3/3]limits 0 to 1.5 =(1.5^3/3)-(0^3/3) =(3.375/3)-(0) =1.125
1.5 1.5 ? x².dx = x³/3 ] 0 (1/3)(1.5³-0³)=1.125
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