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cos 7x – cos 8x= ( cos 7x + cos 3x ) – ( cos 8x + cos 2x ) + ( cos 2x – cos 3x )= ( 2 cos 5x cos 2x ) – ( 2 cos 5x cos 3x ) + ( cos 2x – cos 3x )= ( 2 cos 5x )( cos 2x – cos 3x ) + ( cos 2x – cos 3x )= ( cos 2x – cos 3x ) ( 2 cos 5x + 1 )
divide it by 1+2cos5x to get integrand= cos2x – cos3x. now integrating we get
(1/2)sin2x – (1/3)sin3x + C.
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