Integrate the following with respect to x: -3 ∫ 3 (5x 4 /1+e -x )dx =

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Aditya Gupta · Answer

hello meenu, let J= -3 ∫ 3 (5x 4 /1+e -x )dx …..(1) now, we know by properties of definite integral that we can replace the fn f(x) inside by f(a+b – x) or f( – 3+3 – x)= f( – x) so, J= -3 ∫ 3 (5( – x) 4 /1+e x )dx or J= -3 ∫ 3 (5x 4 /1+e x )dx ….....(2) now, write (1) as J= -3 ∫ 3 (5e x .x 4 /1+e x )dx …......(3) add (2) and (3) 2J= -3 ∫ 3 (5x 4 /1+e x )*(1+e x )dx = -3 ∫ 3 5x 4 dx = x^5| – 3 to 3= 2*3^5 or 2J= 486 so that J = 243 kindly approve :))

Vikas TU · Answer

Dear student For more information please follow this link https://www.askiitians.com/iit-jee-indefinite-integral/solved-examples-of-indefinite-integral.html Good Luck

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Integrate the following with respect to x: -3 ∫ 3 (5x 4 /1+e -x )dx =

Integrate the following with respect to x:
_-3∫³(5x⁴/1+e^-x)dx =

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Integrate the following with respect to x: -3 ∫ 3 (5x 4 /1+e -x )dx =

Integrate the following with respect to x:-3∫3(5x4/1+e-x)dx =

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Integrate the following with respect to x:
_-3∫³(5x⁴/1+e^-x)dx =