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If we are asked to show that siny=x2-1/x2+1 and we are given that where x= tany+secy

If we are asked to show that siny=x2-1/x2+1 and we are given that where x= tany+secy

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Grade:12

1 Answers

Chandan
121 Points
3 years ago
simply put the value of x
we get
siny=tan2y+sec2y+2secy tany-1/(tan2y+sec2y+2secy tany+1)    
in denominator put tan2y+1=sec2y
in numerator put sec2y-1=tan2y
we get
siny=2tan2y+2secy tany/(2sec2y+2secy tany)
taking tany and secy common from numerator and denominator respec.
siny=2tany(secy+tany)/2secy(secy+tany)
siny=tany/secy
siny=siny
hence proved
thankyou

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