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Grade: 12
        
For differential equation 
(1-e^x)sec^2ydy+3e^xtanydx=0
If y(ln2)=pi/4
Then y(ln3) is equal to
one year ago

Answers : (1)

Aditya Gupta
1807 Points
							
first of all put tany=z which means dz=sec^2ydy so the eqn becomes
(1-e^x)dz/dx+3ze^x=0
or dz/z= 3e^xdx/(e^x – 1)
integrate both sides and plug in the initial conditions.
lnz+C=3ln(e^x – 1) 
you can calculate the final answer now
one year ago
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