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Grade 12Integral Calculus

evaluate
∫ ((x^3 + 8)(x – 1)) / x^2 – 2x + 4 dx

taniska

11 Years agoGrade 12

1 Answer

Jitender Singh

11 Years ago

Ans:
Hello Student,
Please find answer to your question below

$I = \int \frac{(x^3+8)(x-1)}{x^2-2x+4}dx$
$I = \int \frac{(x+2)(x^2-2x+4)(x-1)}{x^2-2x+4}dx$
$I = \int (x+2)(x-1)dx$
$I = \int (x^2+x-2)dx$
$I = \int x^2dx+\int x-2\int dx$
$I = \frac{x^3}{3}+\int x-2\int dx$
$I = \frac{x^3}{3}+\frac{x^2}{2}-2\int dx$
$I = \frac{x^3}{3}+\frac{x^2}{2}-2x + c$

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