The no. of solutions of dy/dx = (y+1) / (x -1) , y(1) = 2 is (a)none (b)1 (c) 2 (d)infinite.

The no. of solutions of dy/dx = (y+1) / (x -1)  , y(1) = 2 is

(a)none     (b)1      (c) 2        (d)infinite.


2 Answers

Badiuddin askIITians.ismu Expert
148 Points
14 years ago

Dear Sanchit

dy/dx = (y+1) / (x -1)

dy /(y+1) =dx /(x-1)

ln(y+1) =ln(x-1) + ln c

y+1 =c(x-1)

Given function is not define at x=1

so no solution exits

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Surya Anuraag Duvvuri
39 Points
13 years ago

           dy/dx = (y+1)/(x-1)

          dy/(y+1) = dx/(x-1)

       Taking Integral on both sides,

       ln(y+1) = ln(x-1)+lnC


        Clearly at x=1 it does not exist

       therefore, no solutions exists.

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