Let sn=∑k=1 to n[n/(n2+kn+k2)] and Tn=∑k=0 to (n-1) [n/(n2+nk+k2)] for n=1,2,3....... Then
A Sn‹ pi/3√3 C Tn
B Sn> pi/3√3 D Tn>pi/3√3
Let sn=∑k=1 to n[n/(n2+kn+k2)] and Tn=∑k=0 to (n-1) [n/(n2+nk+k2)] for n=1,2,3....... Then
A Sn‹ pi/3√3 C Tn
B Sn> pi/3√3 D Tn>pi/3√3