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∫cos5x√sinxdx
Hi Suhas,
MAke the sub sinx = t^2, so that cosxdx = 2tdt.
And cos^4x = (1-sin^2 x)^2 = (1-t^4)^2
So that the integral becomes ∫[(1-t^4)^2]2t^2dt.
Open the brackets. Directly integrable.
Hope it helps.
Best Regards,
Ashwin (IIT MadraS).
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