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dear anitha
it will become integral{(tan(x))^2}dx
integral {(tan(x))^2}dx
= integral {(sec(x))^2 - 1}dx [since tan^2(x)+1=sec^2(x)]
= 1/2( tan(x)) -1 [integral{sec^2(x)=tanx]
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Rathod Shankar
IIT Bombay
tan^2x=sec^2x-1
integrate it,
=> tanx-x ans.
integration sec^2(x)/cosec^2(x)
= intg 1/cos^2(x)/1/sin^2(x)
= intg tan^2(x)
=intg sec^2(x)- intg dx
=tanx-x+c
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