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The area bounded by the x-axis and y=cosx and y=sinx when 0 x pi/2 Pls reply with the best soln as fast as possible !!! Always gonna be approved !!! The area bounded by the x-axis and y=cosx and y=sinx when 0<x<pi/2 Pls reply with the best soln as fast as possible !!! Always gonna be approved !!!
The area bounded by the x-axis and y=cosx and y=sinx when 0<x<pi/2
Pls reply with the best soln as fast as possible !!!
Always gonna be approved !!!
f(x) = cosx , g(x) = sinx these two curves intersect at x = pi/4 ,now draw the graphs & u will observe that this area is divided by x = pi/4 so one half area is under sinx & other half is under cosx so area is A = A1 + A2 A = A1 = (sinxdx) lim from 0 to pi/4 + A2 = (cosxdx)lim from pi/4 to pi/2 A = (1 - 1/root2) + (1 - 1/root2) A = 2 - root2 square units
f(x) = cosx , g(x) = sinx
these two curves intersect at x = pi/4 ,now draw the graphs & u will observe that this area
is divided by x = pi/4 so one half area is under sinx & other half is under cosx so area is
A = A1 + A2
A = A1 = (sinxdx) lim from 0 to pi/4 + A2 = (cosxdx)lim from pi/4 to pi/2
A = (1 - 1/root2) + (1 - 1/root2)
A = 2 - root2 square units
ITS AREA =2-ROOT2 Sq.UNITS
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