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(1/x 3 +1).dx please integrate (1/x3+1).dxplease integrate
u can writee 1= x2-(x2-1)the then split it in to twoand write x3+1 in the multiples of x+1 use the mehod of cancellationthen partial diffrentiation and solve
thank ui was just expanding the x cube +1and forgot for the alternative of 1
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