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What is the value of n-fector of [fe (CN)6]^-4Is the given rxn(in the presence of MnO4^-/H^+ (in photo)

Kuldeep , 8 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU
Here n factor measn the valence factor but no Fe further product has been associated but instead MnO4- the n factor here I aassumed as the oxidation state of Fe and that would be => x – 6 = -4
On solving, x = +2.
Last Activity: 8 Years ago
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