Guest

What is the value of n-fector of [fe (CN)6]^-4Is the given rxn(in the presence of MnO4^-/H^+ (in photo)

What is the value of n-fector of [fe (CN)6]^-4Is the given rxn(in the presence of MnO4^-/H^+ (in photo)

Grade:12th pass

1 Answers

Vikas TU
14149 Points
5 years ago
Here n factor measn the valence factor but no Fe further product has been associated but instead MnO4- the n factor here I aassumed as the oxidation state of Fe and that would be => x – 6 = -4
On solving, x = +2.

Think You Can Provide A Better Answer ?