On taking 60.0g CH3COOH and 46.0g CH3CH2OH in a 5L flask in the presence of H3O+(catalyst), at 298 K 44.0g of CH3COOC2H5 is formed at equilibrium. If amount of CH3COOH is doubled without affecting the amount of CH3CH2OH, then CH3COOC2H5 formed is

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Vikas TU · Answer

After doubling the amount, Moles of CH3COOH => 120/60 = 2 moles. Moles of CH3CH2OH => 46/46 = 1 moles. POAC on Carbon, 2 * 2 + 1 * 2 = 2*n we get, n = 6/2 = 3 moles. Mass of CH3COOC2H5 => 3 * 88 = > 264 gm.

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On taking 60.0g CH3COOH and 46.0g CH3CH2OH in a 5L flask in the presence of H3O+(catalyst), at 298 K 44.0g of CH3COOC2H5 is formed at equilibrium. If amount of CH3COOH is doubled without affecting the amount of CH3CH2OH, then CH3COOC2H5 formed is

On taking 60.0g CH3COOH and 46.0g CH3CH2OH in a 5L flask in the presence of H3O+(catalyst), at 298 K 44.0g of CH3COOC2H5 is formed at equilibrium. If amount of CH3COOH is doubled without affecting the amount of CH3CH2OH, then CH3COOC2H5 formed is

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