Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Why nickel does not low spin octrahedral complexes? and why co 2+ gets easily oxidised to co 3+ in presence of a strong ligand?

Why nickel does not low spin octrahedral complexes?


and


why co2+ gets easily oxidised to co3+ in presence of a strong ligand?

Grade:

2 Answers

SAGAR SINGH - IIT DELHI
879 Points
10 years ago

Dear student,

Ni have outer most electronic configuration 4s2 3d8.the hybradisation for octahedral complex is sp2d3.for low spin octahedral complexes the hybradisation is d2sp3.there is two cases for nickle for forming octahedral complexes.
first case: when the ligand is weak then there is no pairing up of electrons in the d-orbital hence there is no d-orbital for acquiring the d2sp3 hybradisation.hence low spin complexes are not formed.
second case:when the ligand is strong there is a pairing up of electrons.but there is only one vacant d-orbital available for hybradisation.so here also d2sp3 hybradisation is not formed.hence low spin octahedral complex is not formed.
thus we can concluded that nickel doesn't forms low sin octahedral complexes.

 

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

All the best.

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar  respectively : Click here to download the toolbar..

 

Askiitians Expert

Sagar Singh

B.Tech, IIT Delhi

Kushagra Madhukar
askIITians Faculty 629 Points
9 months ago
Dear student,
Please find the answer to your question.
 
Ni have outer most electronic configuration 4s2 3d8.the hybradisation for octahedral complex is sp2d3.for low spin octahedral complexes the hybradisation is d2sp3.there is two cases for nickle for forming octahedral complexes.
first case: when the ligand is weak then there is no pairing up of electrons in the d-orbital hence there is no d-orbital for acquiring the d2sp3 hybradisation.hence low spin complexes are not formed.
second case:when the ligand is strong there is a pairing up of electrons.but there is only one vacant d-orbital available for hybradisation.so here also d2sp3 hybradisation is not formed.hence low spin octahedral complex is not formed.
 
Thus we can concluded that nickel doesn't forms low sin octahedral complexes.
 
Co2+is easily oxidised to Co3+in the presence of a strong ligand because in presence of strong ligand the 3d electrons pair up leaving two orbitals empty to be involved in d2sp3 hybridisation.
 
Thanks and regards,
Kushagra

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free