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How do we know the hybidisation of coordination compd. on the basis of Valence Bond Theory. Pls reply urgently How do we know the hybidisation of coordination compd. on the basis of Valence Bond Theory. Pls reply urgently
Dear Student I) The metal ligand bond arises by donation of pair of electrons by ligands to the central metal atom. II) To accommodate these electrons the metal ion must possess requisite number of vacant orbitals of equal energy. These orbitals of the metal atom undergo hybridisation to give hybrid orbitals. III) Sometimes the unpaired (n-1)d orbitals pair up before bond formation making (n-1)d orbitals vacant. The central metal atom makes available number of d-orbitals equal to its co-ordination number. iv) The metal ligand bonds are thus formed by donation of electron pairs by the ligands to the empty hybridized orbitals. These bonds are equal in strength and directional in nature. v) Octahadral, square planar and tetrahedral complexes are formed as a result of d2sp3 (or sp3 d2), dsp2 and sp3 hybridization respectively. Octahedral Complexes Tetrahedral Complexes The tetrahedral arrangement of four ligands surrounding the metal ions. Square Planar Complexes All the best. AKASH GOYAL AskiitiansExpert-IIT Delhi Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar..
Dear Student
I) The metal ligand bond arises by donation of pair of electrons by ligands to the central metal atom.
II) To accommodate these electrons the metal ion must possess requisite number of vacant orbitals of equal energy. These orbitals of the metal atom undergo hybridisation to give hybrid orbitals.
III) Sometimes the unpaired (n-1)d orbitals pair up before bond formation making (n-1)d orbitals vacant. The central metal atom makes available number of d-orbitals equal to its co-ordination number.
iv) The metal ligand bonds are thus formed by donation of electron pairs by the ligands to the empty hybridized orbitals. These bonds are equal in strength and directional in nature.
v) Octahadral, square planar and tetrahedral complexes are formed as a result of d2sp3 (or sp3 d2), dsp2 and sp3 hybridization respectively.
The tetrahedral arrangement of four ligands surrounding the metal ions.
All the best.
AKASH GOYAL
AskiitiansExpert-IIT Delhi
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