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Z^4+1=0 has 4 distinct and non-zero solutions. HOW?
z^4+1=0z^4=-1=cospi+isinpiz^4=cos(2npi+pi)+isin(2npi+pi)z^4=cos(2n+1)pi +i sin(2n+1)pi=e^i(2n+1)piz=e^i(2n+1)pi/4z=e^ipi/4, e^i(3pi/4) , e^i(5pi/4) ,e^i(7pi/4)Thanks & RegardsRinkoo GuptaAskIITians Faculty
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