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`        Volume of oxygen at ntp required to completely burn 2 kg of coal (100%carbon)is`
11 months ago

Arun
22613 Points
```							equation: C + O2 → CO2 1mol C will react with 1 mol O2 Mass ratio 12:32 2 kg coal will require 2 *32/12 = 5.334kg = 5334 g O2 Molar mass O2 = 32g/mol 5334g = 5334/32 = 166.68mol Ar NTP 1 mol = 24L 166.68 mol = 166.68*24 = 4000 L You ask about NTP = my understanding is that at NTP 1 mol gas = 24L But at STP , 1 mol gas = 22.4L At STP , 166.68 mol = 166.68 *22.4 = 3534 L OR 3.534*10^3 L Volume of O2 required art STP = 3.534*10^3 L
```
11 months ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions