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`        The pH of a solution obtained by mixing 50 ml of 0.4 M HCL and 50 ml of 0.2 m in NaOH is.how please explain. `
one year ago

Arun
24510 Points
```							Mole = concentration x volumemole of NaOH = 50ml x 0.2 = 10.0mole of HCl = 50ml x 0.4= 20.010 mole of NaOH exactly neutralized by 10 mole of HCl.NaOH + HCl = NaCl + H2Othat is 20 -10 = 10 HCl moleCon of H+ = no of mole of H+ / total volume of solution (50+50 ml = 100 ml)= 10/100 = 0.1pH = log ( H+)= log (0.1) = 1s0 the pH of solution will be one(1) .
```
one year ago
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• 731 Video Lectures
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions