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Grade: 11
        
The pH of a solution obtained by mixing 50 ml of 0.4 M HCL and 50 ml of 0.2 m in NaOH is.how please explain. 
2 months ago

Answers : (1)

Arun
17859 Points
							

Mole = concentration x volume

mole of NaOH = 50ml x 0.2 = 10.0

mole of HCl = 50ml x 0.4= 20.0

10 mole of NaOH exactly neutralized by 10 mole of HCl.

NaOH + HCl = NaCl + H2O

that is 20 -10 = 10 HCl mole

Con of H+ = no of mole of H+ / total volume of solution (50+50 ml = 100 ml)

= 10/100 = 0.1

pH = log ( H+)

= log (0.1) = 1

s0 the pH of solution will be one(1) .

2 months ago
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