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Grade 12th passIIT JEE Entrance Exam

sir,i am not able to solve this kvpy question,please help me out

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Profile image of aryan patnaik
8 Years agoGrade 12th pass
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1 Answer

Profile image of Arun
6 Years ago
Let us consider the situation in the form of a right angled traingle where ladder forms the hypotenuse, perpendicular is wall and base is the distance of wall and base of ladder. Now we know the various angles of the triangle 90 , 30 and 60(180-90+30) and the length of hypotenuse . Using this calculate the length of other sides by using trigonometric ratios . The ratio comes out to be
H:P:B = 2:√3:1
Now the movemenf along hypotenuse is at a rate of 2m/s so the dispalce ment along base will be at a rate of 1 m/s ( half of hypotenuse