Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
in the figure shown arc ab=3, arc bc=5, arc ac=10 then anle a,b and c are in the figure shown arc ab=3, arc bc=5, arc ac=10 then anle a,b and c are
HiiYou can use cosine law of trinagle in order to find out the angles of triangle.Cosine law of triangle is
HI ISHITA,SO THIS TIME YOU GAVE DIAGRAM. HERE IS THE SOLUTION,AGAIN, JUST SUM THE LENTHS OF ARCS, 3+5+10=18,NOW FIND RATIO FOR EACH ARC,FOR ARC AB ,=3/18FOR ARC BC, =5/18FOR ARC CA, =10/18WE KNOW SUM OF ALL ANGLES OF A TRIANGLE 1800.SO AGAIN YOU CAN FIND BY JUST MULTIPLYING THE RATIO WITH 1800.YOU WILL GET WELL COULD HAVE FOUND THE ANSWER FROM THE PREVIOUS QUESTION,I WILL TELL YOU A PROPERTY, THE RELATION BETWEEN THE ANGLE SUBTENDED BY AN ARC AT THE CENTER OF THE CIRCLE IS DOUBLE OF THE ANGLE MADE BY SAME ARC AT ANY POINT ON THE CIRCLE.IN THE PREVIOUS SOLUTION I GOT ANGLE A = 600 JUST MULTIPLY BY ½ IT MATCHES WITH MY THIS QUESTION ,I HOPE YOU UNDERSTOOD, DONT FORGET TO APPROVE :PHAVE A GOOD DAY :)
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -