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`        If P.E of bohr's hydrogen atom in its ground state is zero. Then its total energy in the first excited sate is? Answer provided Is 23.8eV`
2 years ago

## Answers : (1)

Umakant biswal
5349 Points
```							dear yash i can help you with the correct approach to this question , rest u need to apply the formula and find out . Total Energy of electron, Etotal = Potential energy (PE) + Kinetic energy (KE) For an electron revolving in a circular orbit of radius, r around a nucleus with Z positive charge, PE = -Ze^2/rKE = Ze^2/2rhence Etotal = (-Ze^2/r) + (Ze^2/2r) = -Ze^2/2rAnd for H atom, Z = 1therefore , Etotal = -e^2/2rfirst excited state is 2nd orbit. HOPE IT CLEARS NOW ​all the best regards
```
2 years ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions