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If P.E of bohr's hydrogen atom in its ground state is zero. Then its total energy in the first excited sate is? Answer provided Is 23.8eV

If P.E of bohr's hydrogen atom in its ground state is zero. Then its total energy in the first excited sate is?
 
Answer provided Is 23.8eV

Grade:12

1 Answers

Umakant biswal
5349 Points
7 years ago
dear yash 
i can help you with the correct approach to this question , rest u need to apply the formula and find out . Total Energy of electron, Etotal = Potential energy (PE) + Kinetic energy (KE) 
For an electron revolving in a circular orbit of radius, r around a nucleus with Z positive charge, 
PE = -Ze^2/r
KE = Ze^2/2r
hence 
Etotal = (-Ze^2/r) + (Ze^2/2r) = -Ze^2/2r
And for H atom, Z = 1
therefore , 
Etotal = -e^2/2r
first excited state is 2nd orbit. 
HOPE IT CLEARS NOW 
​all the best 
regards 
 

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