MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
A projectile is observed moving with velocity 50 m/s at an angle 37 degree above the horizontal after one second from its projection. The projectile is projected from the ground and lands on the ground. [g=10m/s2]
Its horizontal range is closest to:-
(1) 80 m (2) 160 m (3) 240 m (d) 320 m
4 months ago

Answers : (1)

Saurabh Koranglekar
askIITians Faculty
3157 Points
							Dear student

Initial velocity be u and angle be theta

U cos theta = 50 cos ( 37) = 40 m/s

50 sin (37) = u sin ( theta) - 10

Usin(theta) = 40

Theta. Is 45
U is 40(sqrt(2))

R = u*u sin( 2 theta) / g

R= 40*40*2/10

R= 320 m

Regards
4 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details