0

Guest

Courses New

A projectile is observed moving with velocity 50 m/s at an angle 37 degree above the horizontal after one second from its projection. The projectile is projected from the ground and lands on the ground. [g=10m/s 2 ] Its horizontal range is closest to:- (1) 80 m (2) 160 m (3) 240 m (d) 320 m

A projectile is observed moving with velocity 50 m/s at an angle 37 degree above the horizontal after one second from its projection. The projectile is projected from the ground and lands on the ground. [g=10m/s2]
Its horizontal range is closest to:-
(1) 80 m (2) 160 m (3) 240 m (d) 320 m

Grade:12th pass

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
Dear student

Initial velocity be u and angle be theta

U cos theta = 50 cos ( 37) = 40 m/s

50 sin (37) = u sin ( theta) - 10

Usin(theta) = 40

Theta. Is 45
U is 40(sqrt(2))

R = u*u sin( 2 theta) / g

R= 40*40*2/10

R= 320 m

Regards

Think You Can Provide A Better Answer ?

Other Related Questions on IIT JEE Entrance Exam

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More