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`        A projectile is observed moving with velocity 50 m/s at an angle 37 degree above the horizontal after one second from its projection. The projectile is projected from the ground and lands on the ground. [g=10m/s2]Its horizontal range is closest to:-(1) 80 m (2) 160 m (3) 240 m (d) 320 m`
6 months ago

Saurabh Koranglekar
3308 Points
```							Dear studentInitial velocity be u and angle be thetaU cos theta = 50 cos ( 37) = 40 m/s50 sin (37) = u sin ( theta) - 10Usin(theta) = 40Theta. Is 45U is 40(sqrt(2))R = u*u sin( 2 theta) / gR= 40*40*2/10R= 320 mRegards
```
6 months ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions