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`        A particle moves along straight line works at a time t a distance x of particle from is given by x is equal to 40 + 12 - 3 Cube how long would the particle travel before coming to rest`
6 months ago

Arun
21438 Points
```							 We have equation x= 40+12t-t^3. So initially take t=0  => x=40m.Now differtiate the equation with respect to time(t) which is equal to velocity (v) {v=dx/dt} now put v=0 as the particle is stopping you will get value of t. Put this value in "40+12t-t^3" and you will get final distance.on Subtracting the initial distance from this final distance we'll get x=16m. RegardsArun (askIITians forum expert)
```
6 months ago
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• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions