Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A composite wire of a uniform cross section 5.5* 10 power minus 5 m square .consists of a steel wire of length 1.5 m and a copper wire of length 2m. by how much will it be stretched when loaded with a mass of 200kg. Young modulus of Steel is 2*10^11 Nm^-2 and copper is 10^11Nm^2.`
11 months ago

vanshith
36 Points
```							A=5.5*10-5  l=1.5mPS+pc--->Delta pYs=F/A÷deltap/ldeltaps=F.P/A.Ys           =2000*1.5/5.5*10-5*2*1011           =3*10-2/55*2           =0.00027mDeltapc=2000*20/5.5*10-5*1011                 =0.00072mDeltap=PS+pc=1mm
```
11 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on IIT JEE Entrance Exam

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions