# When a proton is accelerated through 1 V, then its kinetic energy will be             (a)    1840 eV         (b)    13.6e V         (c)    1 eV         (d)    0.54 eV

Kevin Nash
10 years ago

(c)

Potential difference (V) = 1 V,

K.E. acquired = q V

=      1.6 × 10-19 x 1

=      1.6 × 10-19 joules

=      1 eV

ankit singh
3 years ago
If we accelerate an electron through a potential of 1 kV, it will gain 1 keV of energy. Now the proton has the same amount of charge as an electron. Hence it will also gain 1 keV of energy. The increased mass will mean the final velocity would be less.
Vikas TU
14149 Points
3 years ago
Dear student

ΔKE=qV=eV=e×1×1eV
Hope this will help
Good Luck
Cheers............................................
Arju Kumar
26 Points
3 years ago
Ans (c).
Proton has charge that is “+1e” and when a charge is accelerated through potential then it aquire kinetic energy whiich is equal to charge*potential difference.
So kinetic energy of proton=charge on proton * potential difference
=> kinetic energy of proton= (+1e)*(1V)
=> kinetic energy of proton=1eV