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Grade 11IIT JEE Entrance Exam

26.8 of Na2SO4 × xH2O gave 12.6 g of water on heating. The value of x in the compound is (M. mass of Na2SO4 = 142)

(A) 14 g atoms of nitrogen

(B) 0.6 moles of Sg

(C) 4 g equivalents of sulphate ions

(D) 1.2×1024 chloride ions.

Profile image of Simran Bhatia
12 Years agoGrade 11
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1 Answer

Profile image of Shane Macguire
12 Years ago

Wt. of anhy. Na2SO4 = 26.8 – 12.6 = 14.2 g

 

        14.2 g anhy. Salt combines with water = 12.6 g

 

        142 g anhy. Salt combines with water

 

 

 

        \      H2O (moles) = 126/18 = 7

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