What will be the result if a student connect voltmeter in a series and a ammeter in parallel in a circuit by mistake?

By the presence of voltmeter in series with resistance R in a circuit due to voltmeter`s high resistance the current I(=V/R) will get decreases to I`1(=V/R) and as I`1 will divide in resistance and ammeter the current through ammeter I`2 will ever lesser than I`1. Also the P.D will divide across the resistance and voltmeter, so the P.D across V`2 will lesser than V. Since I`2 and V`2 both are lesser than I and V respectively, none of the instruments will be damage