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`        two bodies of diferrent masses Ma and Mb are dropped from same  height  h .what is the ratio of time taken by the two bodies to fall through this ditance`
2 years ago

Sanju
106 Points
```							We have, s = ut+ 0.5 at2 where, s = height, u = initial velocity, t= time taken and a = acclrn due to gravityHere u = 0So the eqn becomes s = 0.5 at2Or, t = sqrt(2s/g)This relation shows that time depends on the height only and is independent of the mass.Therefore, ratio of time taken is:t1 / t2 = sqrt (s1 / s2)
```
2 years ago
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