The uniform gate weighs 300N and is 3m wide and 2m high. It is supported by a hinge at the bottom left corner and a horizontal cable at the top left corner. Find tension in the cable and force exerted by hinge on the gate.

Question

Saurabh Koranglekar · Answer

FromFBD
The equation in the horizontal direction
T=Nx……(1)T=Nx……(1)
For Rotational equation aboutPP
T.2=1.5×300T.2=1.5×300
T=225NT=225N
Nx=225NNx=225N
Ny=300NNy=300N
AndNg=mg=300N

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The uniform gate weighs 300N and is 3m wide and 2m high. It is supported by a hinge at the bottom left corner and a horizontal cable at the top left corner. Find tension in the cable and force exerted by hinge on the gate.

The uniform gate weighs 300N and is 3m wide and 2m high. It is supported by a hinge at the bottom left corner and a horizontal cable at the top left corner. Find tension in the cable and force exerted by hinge on the gate.

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The uniform gate weighs 300N and is 3m wide and 2m high. It is supported by a hinge at the bottom left corner and a horizontal cable at the top left corner. Find tension in the cable and force exerted by hinge on the gate.

The uniform gate weighs 300N and is 3m wide and 2m high. It is supported by a hinge at the bottom left corner and a horizontal cable at the top left corner. Find tension in the cable and force exerted by hinge on the gate.

1 Answers

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Other Related Questions on General Physics

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