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The escape velocity of projection from the earth is approximately (R = 6400 km) (a) 7 km/sec (b) 112 km/sec (c) 12.2 km/sec (d) 1.1 km/sec

The escape velocity of projection from the earth is approximately (R = 6400 km)
(a) 7 km/sec
(b) 112 km/sec
(c) 12.2 km/sec
(d) 1.1 km/sec

Grade:12th pass

1 Answers

Unicorn
96 Points
2 years ago
1/2 mv^2= GMm/r 
 
V escape =root 2GM/r
Putting values of radius and constants we get 
Vescape =11.2 km/sec
 

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