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Grade 12th passGeneral Physics

The escape velocity of projection from the earth is approximately (R = 6400 km)
(a) 7 km/sec
(b) 112 km/sec
(c) 12.2 km/sec
(d) 1.1 km/sec

Profile image of Bibhu Ranjan Chakraborty
4 Years agoGrade 12th pass
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1 Answer

Profile image of Unicorn
4 Years ago
1/2 mv^2= GMm/r 
 
V escape =root 2GM/r
Putting values of radius and constants we get 
Vescape =11.2 km/sec