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`        The earth revolves around the sun in a circular path with a speed of 30km/s. What is the radial acceleration directed towards the sun`
3 months ago

```							Dear student Speed of revolution = 30Km/s                               = 3 x 10 ^4 m/sTime of revolution = One year = 356 days (convert into seconds)                            = 365 x 24 x 60 x 60 = 3.5 x 10 ^7 secondsThe formula of radial acceleration:                     ac = V^2 / rDistance covered by the earth around the sun will be equal to the circumference of orbit.      Speed x Time ( V.T ) = 2πr                               r = V.T/2π                        ac = V2 / r = V ^2 x 2π/V.T                                ac = 2πV /T                              ac = 2 x 3.14 x 3 x 10 ^4/ 3.5 x 10 ^7                                ac = 5.98 x 10 ^-3 m/s2
```
3 months ago
```							Here, the Earth revolves around the sun in a circular path with a speed of 30 km per secondSpeed of revolution = 30 km/s = 3 * 10⁴ m/s.Time of revolution = 1 year = 365 * 24 * 60 * 60 = 3.15 * 10⁷ sec=> Radial acceleration, a_c = v₂/ rDistance covered by Earth = circumference of orbitV.T = 2πrr = V.T / 2π∴ a_c = v² / r= v² 2π / v T= 2πV / T= 2π * 3 * 10⁴ / 3.15 * 10⁷= 5.98 * 10⁻³ m/s²Thus, a radial acceleration directed towards the sun​ is 5.98 * 10⁻³ m/s²
```
3 months ago
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