Flag General Physics> An object is thrown vertically up from th...
question mark

An object is thrown vertically up from the ground passes the height 5 m twice in an interval of 10 secs. what is the time of flight?
1)280.5
2)860.5
3)1040.5
4)720.5

anirban deb , 11 Years ago
Grade 11
anser 2 Answers
bharat bajaj
s = ut + 1/2. a.t^2 .....
5 = ut - 5t^2 .....
5t^2 - ut + 5 = 0 ...
The roots of this equation gives us the time at which particle crosses the height 5 m....If we calculate the difference of roots, it tells us the interval which we know is 10 s...
Say roots are a and b....a-b = ( (a+b)^2 - 4ab ) ^0.5....a - b = ( u^2/25 - 4)^0.5....100 = u^2/25 - 4..
u = 5.(104)^0.5...Total time of flight = 2u/a = (104)^0.5..THanks
Bharat BajajIIT Delhi
askiitians faculty
Last Activity: 11 Years ago
Arun Kumar
Hello
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty
Last Activity: 11 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments