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A particle moves moved in the x-y plane under the action of a force vector F such that the value of its linear momentum vector P at anytina t is Px=2cost, Py=2sint.The angle between vector F and vector P at a given time to will be
A particle moves moved in the x-y plane under the action of a force vector F such that the value of its linear momentum vector P at anytina t is Px=2cost, Py=2sint.The angle between vector F and vector P at a given time to will be

```
2 years ago

```							Given:  Px= 2 cos t,  Py =2 sin tP = Px i + Py j = 2 cos t i + 2 sin t jNow according to the Newton's second law we can calculate components of forces using respective momentum component as:  F = dp/dtFx = - 2 sin tFy = 2 cos tF =  Fx i + Fy j = -2 sin t i + 2 cos t jLets try to find out the dot product of F and P,F P = 0 -------------(3)but we do know that dot product of force and momentum can also be given in the form of angle between them asF P = FP cos θ ---------------------(1)Comparing both equations ⇒ θ = 90°
```
2 years ago
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