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`        A particle is projected with a velocity of A 20m/s in air at an angle alpha with horizontal. The x and y coordinates lying on trajectory of the particle with respect to point of projection R, 20m and 8m respectively. Find the angle of projection of the particle.`
one month ago

Shivam Agrawal
14 Points
```							Let the point of projection have the coordinates (0,0). Then the coordinates after ‘t’ time is [20*t*cos(alpha), 20*t*sin(alpha)].Coordinates given (20,8) Therefore, 20*t*cos(alpha) = 20t*cos(aplha) = 1    -------------- (1) 20*t*sin(alpha) = 8t*sin(alpha) = 2/5    ---------------(2) Dividing equation (2) by (1) [t*sin(alpha)] / [t*cos(alpha)] = 2/5tan(alpha) = 2/5alpha = tan-1(2/5) Angle of Projection = tan-1(2/5)
```
one month ago
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