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`        A drunkard is walking along a straight road.  He takes 5 steps forward and 3 steps backward,  followed by 5 steps forward and 3 steps backward and so on. Each step is one meter long and takes one second. There is a pit on the road 11 meter away from the starting point then after how much time drunkard will fall into the pit?`
3 years ago

Vikas TU
10073 Points
```							For  8 total steps it takes 8 seconds, and moves in total 2 steps forward (2 m) Therfore,3*2 m = 6 m At 3rd cycle Time Elapsed  24 s After walking 5 m forward, he takes 5 s more. It becomes 11 m. Time = 24 + 5 = 29m
```
3 years ago
Saurav
13 Points
```							2m-8sec4m-16secAnd so on,,, 4*6=24 And it will need 5sec more to fell down in yard so 24+5=29sec ,,,thanks.  ,,,,,,
```
2 years ago
Krrish
11 Points
```							Distance covered with 1 step = 1 mTime taken = 1 sTime taken to move first 5 m forward = 5 sTime taken to move 3 m backward = 3 sNet distance covered = 5 – 3 = 2 mNet time taken to cover 2 m = 8 sDrunkard covers 2 m in 8 s.Drunkard covered 4 m in 16 s.Drunkard covered 6 m in 24 s.Drunkard covered 8 m in 32 s.In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s
```
2 years ago
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