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        A car is standing 200 m behind a bus, which is also at rest. The two start moving at the same instant but with different forward accelerations. The bus has acceleration 2 m/s2 and the car has acceleration 4 m/s2 . The car will catch up with the bus after a time of
2 years ago

Arun
23742 Points
							Dear Pritam  Distance between car and bus = 200mAcceleration of bus                   = 2m/s2Acceleration of car                    = 4m/s2Relative acceleration of car with respect to bus = 4m/s2 – 2m/s2 = 2m/s2EXPLANTION- Imagine you are sitting in the bus and which starts moving in forward direction with an acc. of 2m/s2 and a car follows you with an acc. 4m/s2. Therefore acceleration of car with respect to you (that is as seen by you) would be 2m/s2.therefore distance(S) = 200m , initial velocity = 0 (since at rest), relative acc. = 2m/s2Applying second equation of motion S = ut + 1/2at2 200 = 0 + 1/2*2*t2t2 = 200t = 10$\large \sqrt$2 sect = 14.14 sec RegardsArun (askIITians forum expert)

2 years ago
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