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`        A ball is thrown vertically upward from the foot of a tower. it crosses the top of the tower twice after an interval of 4s and reaches the foot of the tower 8s after its was thrown. what is the height of the tower`
2 years ago

Arun
23742 Points
```							Dear Samresh time taken to go upto U and then come back to the ground required 8 sec.So 4 s up then 4 s in coming down.the time taken between climbing from T to U and then coming to T again(crossing T twice) =4 sso time taken to go upto T from the ground=(8 - 4)/2=2snow if we consider the journey from ground to U:0=u-4x10 .......  putting in 1st eq.u=40 m/snow tower height:H=H=40x2-1/2  x10x2x2.....putting in second eqH=60 m RegardsArun (askIITians forum expert)
```
2 years ago
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