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a ball is thrown vertically into the air at 120 m/s. after 3 seconds, another ball is thrown vertically. what is the velocity must the second ball have to pass the first ball at 100m from the ground?
Here,100m=120t-10/2t2Solve for t and thenplace it --s=u(t-3)-5(t-3)2you will get value of u.I don’t know the answer and have no idea whether it is in decimal or in fraction or a whole no. Please try to solve it on your own
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