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A particle is thrown vertically upward. Its velocity at half of the height is 10m/s. Find the maximum height attained by it if g=10m/s2.

147 Points
11 years ago

Dear abhingya

let intitial velocity is U and maximum hight is h

so at maximum hight velocity will be zero

0 =U2 -2gh

U2 =2gh ..........1

now given velocity is = 10m/sec at hight h/2

so 102 = U2 -2gh/2

100 =2gh -gh

h = 100/10

h =10 m/sec

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15 Points
3 years ago
The above and is correct but the and has a silly mistake in the last h =10 m/ s it should be h=10 m and was this a real iitian plz ans
one year ago
Dear student,

Let intitial velocity is U and maximum hight is h
so at maximum hight velocity will be zero
0 = U2 – 2gh
U2 = 2gh ..........1
now given velocity is = 10m/sec at hight h/2
so 102 = U2 – 2gh/2
100 = 2gh – gh
h = 100/10
h = 10 m

Thanks and regards,
Kushagra