Guest

A person is holding a bucket by applying vertical force of 10 N. He moves it horizontally to a distance of 5m and then climbs up a vertical distance of 10m . calculate work done by him.

A person is holding a bucket by applying vertical force of 10 N. He moves it horizontally to a distance of 5m and then climbs up a vertical distance of 10m . calculate work done by him.

Grade:Upto college level

2 Answers

Sumit Majumdar IIT Delhi
askIITians Faculty 137 Points
8 years ago

Dear student,

The person would be doing work only when the distance coveered is along the same direction as the force applied. In this case, the total displacement can be represented as:

r=(5i+10j)

and the force can be represented as:

F=10j

So, the net work done, would be equal to:

W=F.r=100 J

Thanks & Regards
Sumit Majumdar, 
askIITians Faculty
Ph.D, IIT Delhi

Chetan Patil
31 Points
8 years ago

We have relation Work(k) = Force(f).Displacement(s)=f.s.cosΘ  Θ=900 when bucket is moved horizantaly.When it moved upward w=f.s cosΘ=10x10x1=100 J because Θ=00

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free