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Dear student,
The person would be doing work only when the distance coveered is along the same direction as the force applied. In this case, the total displacement can be represented as:
r=(5i+10j)
and the force can be represented as:
F=10j
So, the net work done, would be equal to:
W=F.r=100 J
We have relation Work(k) = Force(f).Displacement(s)=f.s.cosΘ Θ=900 when bucket is moved horizantaly.When it moved upward w=f.s cosΘ=10x10x1=100 J because Θ=00
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