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# what is the mass of a sphere of diameter 1cm whose density is 900 kg/m^3

8 years ago

Volume=4/3pi x (0.5)3

=0.52 cm3

= 0.52 x 10-6 m3

Mass= Density x Volume

= 900 x 0.52x10-6  kg

=0.468 g

8 years ago

density = mass/ volume

given denstiy = 900kg/m3 and diameter = 1cm so radius(R) = 0.5 cm = 0.005m

900 = mass/ (4/3 π R3 )

Mass = (900*3 π R3 )/4 = (900*3* π *(0.005)3 )/ 4 = 2.650718801×10?4 Kg naninagaraju sivacharan lakshmi narsing
34 Points
8 years ago

given diameter of the sphere=1cm

=1/2=0.5cm

density of the sphere=900kg/m^3

formula: density=mass/volume

volume of the sphere =4/3 pi r^3

mass=density*volume

==>900*4/3*3.14*(0.5*10^-2m)^3

===>4.71*10^-4

Thanks for asking these type of questions

8 years ago

mass=volume * density.By using this formula we can find the mass of sphere.

Volume of sphere=(4/3)pi*r^3

V=(4/3)*3.14*(1*10^-2)^3=4.187*10^-6

Mass=(4.187*10^-6)*900=3768*10^-6kg