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what is the mass of a sphere of diameter 1cm whose density is 900 kg/m^3
radius=0.5cm
Volume=4/3pi x (0.5)3
=0.52 cm3
= 0.52 x 10-6 m3
Mass= Density x Volume
= 900 x 0.52x10-6 kg
=0.468 g
radius=.5
volume=4∏r3/3
v=5.2333333333334*10-7m3
mass=density *volume
mass=
5.2333333333334*10-7m3*900kg
0.000471kg
density = mass/ volumegiven denstiy = 900kg/m3 and diameter = 1cm so radius(R) = 0.5 cm = 0.005m900 = mass/ (4/3 π R3 )Mass = (900*3 π R3 )/4 = (900*3* π *(0.005)3 )/ 4 = 2.650718801×10?4 Kg
given diameter of the sphere=1cm
so that the radius is=diameter/2
=1/2=0.5cm
density of the sphere=900kg/m^3
formula: density=mass/volume
volume of the sphere =4/3 pi r^3
where r=radius of the sphere
mass=density*volume
==>900*4/3*3.14*(0.5*10^-2m)^3
===>4.71*10^-4
Thanks for asking these type of questions
mass of the sphere is = 4.713 × 10^−4 kg
mass=volume * density.By using this formula we can find the mass of sphere.
Volume of sphere=(4/3)pi*r^3
V=(4/3)*3.14*(1*10^-2)^3=4.187*10^-6
Mass=(4.187*10^-6)*900=3768*10^-6kg
Mass = 3.77 x 10-3 kg..
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