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A ball is dropped from a height of 1m. How long does it take for the ball to reach theground? With what speed does it hit the ground?
I GOT ANSWERS=0.14s;1.4 m/s respectively.
IS not my answer correst? BOOK HAS ANSWER PRINTED 0.45s; 4.4m/s.
initial velocity is zero so final velocity when it reaches ground is sqrt(2gh), where h is the height of fall......so velocity sqrt(2*9.8*1)=4.4 m/s
the time taken for fall t=velcity divided by acceleration........t=4.4/9.8=0.45 seconds.........
dear friend,the book is correct. since u=0,h=1m .now apply 2nd and 3rd law..you will get the correct answer.
v^2=2*g
v^2=20
v=4.4m/s
t=v/g
t=.44s
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