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A wheel of moment of inertia 0.2 kgm 2 rotates at 360 rpm, about its vertical axis. What is the angular speed of the wheel, when a torque of -1Nm is applied about the same axis for 3s is


A wheel of moment of inertia 0.2 kgm2 rotates at 360 rpm, about its vertical axis. What is the angular speed of the wheel, when a torque of -1Nm is applied about the same axis for 3s is


 


Grade:12

3 Answers

harsh vardhan awasthi
14 Points
9 years ago

is your answer 3(4pi + 5) rad/sec?

Kumar Gaurav
33 Points
9 years ago

TORQUE=MOMENT OF INERTIA*ALPHA(ANGULAR ACCELERATION)

-1=0.2*ALPHA

=-5m/s^2

appliying equation of motion for angle

final omega=initial omega-alpha*time

                =120pi-0.5*3

                =120pi-1.5

xyz xz
37 Points
8 years ago

12∏-15

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