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Grade: 12
        


A wheel of moment of inertia 0.2 kgm2 rotates at 360 rpm, about its vertical axis. What is the angular speed of the wheel, when a torque of -1Nm is applied about the same axis for 3s is


 


7 years ago

Answers : (3)

harsh vardhan awasthi
14 Points
							

is your answer 3(4pi + 5) rad/sec?

7 years ago
Kumar Gaurav
33 Points
							

TORQUE=MOMENT OF INERTIA*ALPHA(ANGULAR ACCELERATION)

-1=0.2*ALPHA

=-5m/s^2

appliying equation of motion for angle

final omega=initial omega-alpha*time

                =120pi-0.5*3

                =120pi-1.5

7 years ago
xyz xz
37 Points
							

12∏-15

7 years ago
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