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A bomb is dropped from an aeroplane, whe it is directly above a target at a height of 1500m. The aeroplane is going horizontally with a speed of 500km/h. By how much distance will the bomb miss the target ?
1/2 GT2 = H ,get time (vertical velocity is zero)
horizontal dierction has no acceleration, therefore D is VT. D is the disrance by which it missed.
1500 = 1/2gt 2
get the time from here and put it ;
x = vt
v = 500 x 5/18 in mks units .
and now substitute for x to get ur answer
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