A person walking at 4m/s finds rain drops falling slantwise to his face with a speed of 4m/s at an angle of 30 degrees with the vertical. Show that the actual speed of the rain drops is 4m/s

Question

rupali sehgal · Answer

Velocity of rain wrt man= 4m/sat an angle 30º with vertical (given)

velocity of man wrt ground = 4m/s

from fig.

velocity of rain wrt man + velocity of man wrt ground = velocity of rain wrt ground (triangle law of vector addition)

so, velocity of rain wrt ground = √(4)² + (4)² + 2(4)(4)cos 120

= √ 16+16+32(-0.5)

=√32-16

=√16 = 4m/s

hence proved!

Krishna · Answer

Vrm=4 m/s Theta=30° Vmg= 4 m/s According to triangle law of vectors, Velocity of man w.r.t ground, Vrg =Vrm + Vmg =Vrg =√4*4 + 4*4 + 2*4*4cos120 =√32 - 16 =√16 =4 Hence proved

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A person walking at 4m/s finds rain drops falling slantwise to his face with a speed of 4m/s at an angle of 30 degrees with the vertical. Show that the actual speed of the rain drops is 4m/s

A person walking at 4m/s finds rain drops falling slantwise to his face with a speed of 4m/s at an angle of 30 degrees with the vertical. Show that the actual speed of the rain drops is 4m/s

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