The position of a particle moving in a straight line is given by y=3t^3 + t^2 +5 (y in cm and t in second) then, find the acceleration of the particle at time t=2 second
Rohit Das , 12 Years ago
Grade
1 Answers
rashmi mehlawat
Last Activity: 12 Years ago
velocity of this will be 9t^2+2t+0 after differentiation.acc will be futher 18t+2.so at t=2.answer is 38!acc=dv/dt.and v=velocity.......................is dp/dt.....i.e p=position.ANY DOUBTS IN PHY mail me at rashmi_mehlawat@yahoo.com
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free