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The position of a particle moving in a straight line is given by y=3t^3 + t^2 +5 (y in cm and t in second) then, find the acceleration of the particle at time t=2 second
velocity of this will be 9t^2+2t+0 after differentiation.acc will be futher 18t+2.so at t=2.answer is 38!acc=dv/dt.and v=velocity.......................is dp/dt.....i.e p=position.ANY DOUBTS IN PHY mail me at rashmi_mehlawat@yahoo.com
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