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the velocity of a particle moving along x axis is given by -
v = 32 t ^2 - 2t^3 m/s. what is the accelaration of the particle after maximum displacemen is achieved?
at maximum displacement,dx/dt=v=0, 32t^2=2t^3,t=16s, a=dv/dt=64t-6t2=64*16-6*162
in this case, if we compute the answer is -512 m/sec^2. But the actual answer is -64m/sec^2. can someone tell how?
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