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the velocity of a particle moving along x axis is given by -v = 32 t ^2 - 2t^3 m/s. what is the accelaration of the particle after maximum displacemen is achieved?

goutham 1995 gumm , 13 Years ago
Grade 12
anser 2 Answers
Chetan Mandayam Nayakar

Last Activity: 13 Years ago

at maximum displacement,dx/dt=v=0, 32t^2=2t^3,t=16s, a=dv/dt=64t-6t2=64*16-6*162

 

goutham 1995 gumm

Last Activity: 13 Years ago

in this case, if we compute the answer is  -512 m/sec^2. But the actual answer is -64m/sec^2. can someone tell how?

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