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a nucleus (mass no 238)initially at rest decay into another nucleus(mass no 234)emitting an alpha particle(mass no 4)with speed of 1.17*10to the power 7m/sec.find the speed of remaining nucleus

a nucleus (mass no 238)initially at rest decay into another nucleus(mass no 234)emitting an alpha particle(mass no 4)with speed of 1.17*10to the power 7m/sec.find the speed of remaining nucleus

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1 Answers

saiharsha vaddempudi
30 Points
9 years ago

Intially the momentum of mass no 238 i.e. uranium nucleus is zero as it at rest . After emission of the alpha particle the sum of momenta of alpha particle and remaining mass no 234 i.e. thorium is also zero ,because the radioactive emmision is purely internal process and no external force acts upon it . thus  

  multiplication of mass alpha and velocityalpha+ multiplication of  massthorium and velocitythorium  =0  (according to law of conservation of momentum) , so 

          velocity of thorium = -malpha particle  / mthorium  into velocityalpha 

                          we know that massalpha / mass thorium = 4/234 

  given valpha = 1.17 into 107   so  velocity of thorium = -4/234 into 1.17 into 107 

                                                                           = - 2 into 105 m/s here minus represents direction

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